FCC Exam Question: 3-32D6
With a pure AC signal input to the circuit shown in Figure 3D11, what output wave form would you expect to see on an oscilloscope display?
Explanation: Figure 3D11 typically illustrates a **half-wave rectifier** circuit, which consists of a single diode in series with a load. When a pure AC (alternating current) sine wave is applied to this circuit, the diode acts as a one-way valve for current. During the positive half-cycle of the AC input, the diode is forward-biased and conducts, allowing the positive portion of the sine wave to pass through to the output. During the negative half-cycle, the diode is reverse-biased and blocks the current, preventing the negative portion of the sine wave from reaching the output. Therefore, the output waveform on an oscilloscope will show only the positive half-cycles of the original AC input, with the negative half-cycles suppressed. This precisely matches **waveform 2**. * Waveform 1 would be expected from a full-wave rectifier circuit. * Waveform 3 suggests a filtered DC output, which would require a capacitor in addition to the rectifier. * Waveform 4 is the original AC input, implying no rectification occurred.
3-10B3
3-3A5
3-57H1
3-80L1
3-93O6
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Includes Elements 1, 3, 6, 7R, 8, and 9.