FCC Exam Question: 3-93O6

To couple energy into and out of a waveguide use:

A. Wide copper sheeting.
B. A thin piece of wire as an antenna.
C. An LC circuit.
D. Capacitive coupling.
Correct Answer: B

Explanation: Waveguides transmit electromagnetic energy as propagating waves within their hollow metallic structure. To couple energy into or out of a waveguide, a device is needed that can efficiently interact with these internal electric and magnetic fields. A thin piece of wire, acting as a small antenna (often called a probe or loop), is precisely this device. When RF current is applied to a probe extending into the waveguide, it creates an oscillating electric field that excites and launches the electromagnetic wave into the waveguide. Conversely, a propagating wave inside the waveguide induces a current in the probe, transferring energy out. The length of the probe is typically optimized (e.g., a quarter-wavelength) for resonance and maximum energy transfer at the operating frequency, much like a conventional antenna. Wide copper sheeting would block or reflect the wave. An LC circuit is used for tuning and filtering but doesn't directly couple energy into the waveguide's electromagnetic field. While a probe can exhibit capacitive or inductive characteristics, "capacitive coupling" is a general term and doesn't fully describe the resonant antenna action required for efficient waveguide coupling.

Pass Your FCC Exam!

Study offline, track your progress, and simulate real exams with the GMDSS Trainer app.


Includes Elements 1, 3, 6, 7R, 8, and 9.