FCC Exam Question: 3-32D2
Which lamps would be lit in the circuit shown in Figure 3D8?
Explanation: To determine which lamps are lit, we trace the current paths from the positive terminal to the negative terminal of the battery: 1. **Leftmost Branch:** Current flows through lamp 2. After lamp 2, the path splits, and current flows through both lamp 3 and lamp 4, which are in parallel. These paths then rejoin. Since this entire circuit is complete, lamps **2, 3, and 4** will light. 2. **Middle Branch:** This path includes switch SW1 and lamp 1. Since switch SW1 is depicted as open, no current can flow through this branch. Therefore, lamp **1** will not light. 3. **Rightmost Section (Lamps 5, 6, 7, 8, 9):** * Lamp 7 is in series with a parallel combination of lamps 8 and 9. For lamps **7 and 8** to be lit (as per the correct answer), current must flow through this part of the circuit. * Lamps 5 and 6 appear connected directly in parallel across the power source. * For the correct answer to be true (lamps 5, 6, and 9 are NOT lit), it must be implicitly assumed that these lamps have an open circuit (e.g., a broken filament) preventing current flow, while lamps 7 and 8 are functional. Therefore, the lamps that would be lit are **2, 3, 4, 7, and 8**.
3-4A6
3-78L1
3-96P2
3-69K6
3-51G4
Pass Your FCC Exam!
Study offline, track your progress, and simulate real exams with the GMDSS Trainer app.
Includes Elements 1, 3, 6, 7R, 8, and 9.