FCC Exam Question: 8-14B1

The pulse developed by the modulator may have an amplitude greater than the supply voltage. This is possible by:

A. Using a voltage multiplier circuit.
B. Employing a resonant charging choke.
C. Discharging a capacitor through an inductor.
D. Discharging two capacitors in series and combining their charges.
Correct Answer: B

Explanation: The ability of a modulator pulse to exceed the supply voltage is a phenomenon leveraged in high-power pulse generation. **Correct Answer: B) Employing a resonant charging choke.** A resonant charging choke is integral to pulse-forming networks (PFNs) used in many modulators. When a capacitor in a PFN is charged through an inductor (the choke) from a DC supply, the series LC circuit can resonate. If the circuit's Q factor is high enough, the voltage across the capacitor can "ring" up to approximately twice the DC supply voltage. This occurs because the inductor stores energy, and as the capacitor charges to the supply voltage, the inductor continues to push current, transferring its stored energy to the capacitor, thereby overcharging it. This higher voltage then forms the basis for the modulator's high-amplitude output pulse. **Why other options are incorrect:** * **A) Using a voltage multiplier circuit:** While voltage multipliers increase DC voltage, they typically provide a sustained higher DC output, not a high-amplitude pulse directly from a modulator's discharge action. * **C) Discharging a capacitor through an inductor:** This describes the formation of the pulse itself (an LC discharge), but doesn't explain how the capacitor was initially charged to a voltage *greater than* the supply. Resonant charging is the mechanism for that initial overcharge. * **D) Discharging two capacitors in series and combining their charges:** Discharging capacitors in series will sum their voltages, but it doesn't explain how the individual capacitors acquired a charge voltage greater than the supply in the first place.

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Includes Elements 1, 3, 6, 7R, 8, and 9.