Explanation: This question applies Ohm's Law and the principles of series circuits. In a series circuit, the total current (I) is the same through all components, and the total resistance (R_total) is the sum of individual resistances (R1 + R2). If we assume the "3" refers to a current of 3 Amperes (A), then to achieve a total voltage (V) of 200 V (option A), the total resistance of the two series resistors must be 66.67 ohms. This is derived from Ohm's Law, V = I * R, rearranged to R = V / I. So, R_total = 200 V / 3 A = 66.67 Ω. Therefore, if the series resistors combined to 66.67 ohms, a 3 A current passing through them would result in a total voltage drop of 200 V. The other voltage options would imply different total resistance values for the same 3 A current, making them incorrect in this context.