FCC Exam Question: 3-9B5
If a current of 3 amperes flows through a resistor connected to 90 volts, what is the resistance?
A. 3 ohms.
B. 30 ohms.
C. 93 ohms.
D. 270 ohms.
Correct Answer: B
Explanation: This question applies Ohm's Law, a fundamental principle in electronics and amateur radio theory. Ohm's Law describes the relationship between voltage (V), current (I), and resistance (R) in a circuit. It is typically expressed as V = I × R. To find the resistance (R) when voltage and current are known, you can rearrange the formula to: R = V / I Plugging in the given values: R = 90 volts / 3 amperes R = 30 ohms Therefore, a resistance of 30 ohms is required for 3 amperes to flow at 90 volts. Options A, C, and D are incorrect as they do not result from the correct application of Ohm's Law with the provided values.
Related Questions
3-63J4
3-15B1
3-70K3
3-47F2
3-6A5
Pass Your FCC Exam!
Study offline, track your progress, and simulate real exams with the GMDSS Trainer app.
Includes Elements 1, 3, 6, 7R, 8, and 9.