FCC Exam Question: 3-74L2

A 50 microampere meter movement has an internal resistance of 2,000 ohms. What applied voltage is required to indicate half-scale deflection?

A. 0.01 volts
B. 0.10 volts
C. 0.005 volts.
D. 0.05 volts.
Correct Answer: D

Explanation: To determine the voltage required for half-scale deflection, we apply Ohm's Law, V = I * R. First, calculate the current for half-scale deflection. The meter's full-scale deflection (FSD) is 50 microamperes (µA). Half-scale deflection therefore corresponds to a current of 50 µA / 2 = 25 microamperes. In amperes, this is 0.000025 A. Next, use Ohm's Law with this current and the given internal resistance: V = I * R V = (0.000025 A) * (2,000 Ω) V = 0.05 volts. Therefore, an applied voltage of 0.05 volts is required to indicate half-scale deflection. Option B, 0.10 volts, would be the voltage for full-scale deflection (50 µA * 2,000 Ω = 0.10 V), not half-scale. Options A and C are incorrect values.

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Includes Elements 1, 3, 6, 7R, 8, and 9.