FCC Exam Question: 3-66J5
Referred to the fundamental frequency, a shorted stub line attached to the transmission line to absorb even harmonics could have a wavelength of:
Explanation: A shorted stub that is 1/4 wavelength long at the fundamental frequency presents a very high impedance (an open circuit) at its input. When attached in parallel to a transmission line, it allows the fundamental frequency and its odd harmonics (which also see an effective open circuit, e.g., 3/4 wavelength for the 3rd harmonic) to pass with minimal attenuation. However, at the second harmonic, this same stub is effectively 2 * (1/4 wavelength) = 1/2 wavelength long. A 1/2 wavelength shorted stub acts as a short circuit at its input. This shunts and absorbs the second harmonic from the transmission line. This principle applies to all even harmonics (e.g., the 4th harmonic sees a 1-wavelength shorted stub, which is also a short circuit), making the 1/4 wavelength stub ideal for suppressing them.
3-89N3
3-67J1
3-96P1
3-80L4
3-91O2
Pass Your FCC Exam!
Study offline, track your progress, and simulate real exams with the GMDSS Trainer app.
Includes Elements 1, 3, 6, 7R, 8, and 9.