Explanation: To determine the total current flow, first calculate the equivalent resistance of the two parallel light bulbs. For two equal resistors in parallel, the equivalent resistance is half of one resistor: $R_{parallel} = \frac{12 \text{ ohms}}{2} = 6 \text{ ohms}$. Next, sum this parallel resistance with the battery's internal resistance, which is in series with the bulbs, to find the total circuit resistance: $R_{total} = R_{parallel} + R_{internal} = 6 \text{ ohms} + 1.2 \text{ ohms} = 7.2 \text{ ohms}$. Finally, apply Ohm's Law ($I = \frac{V}{R}$) to find the total current: $I = \frac{6 \text{ volts}}{7.2 \text{ ohms}} \approx 0.833 \text{ amps}$. This calculation matches option B. The other options result from incorrect resistance calculations or Ohm's Law application.