FCC Exam Question: 3-55G6
What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?
Explanation: To determine the voltage across the dummy load, we use the fundamental electrical power formula that relates power (P), voltage (V), and resistance (R): P = V²/R To find the voltage (V), we rearrange the formula: V = sqrt(P * R) Given: Power (P) = 1,200 watts Resistance (R) = 50 ohms Substitute the values into the formula: V = sqrt(1,200 watts * 50 ohms) V = sqrt(60,000) V ≈ 244.95 volts Rounding to the nearest whole number, the voltage is 245 volts. Options B, C, and D are incorrect because they result from misapplying the power formula, such as incorrectly dividing instead of multiplying, or taking the square root of only part of the equation.
3-86N1
3-5A1
3-3A1
3-88N5
3-89N1
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Includes Elements 1, 3, 6, 7R, 8, and 9.