FCC Exam Question: 3-17B3

In polar coordinates, what is the impedance of a network composed of a 400-ohm-reactance capacitor in series with a 300-ohm resistor?

A. 240 ohms, /36.9 degrees
B. 240 ohms, /-36.9 degrees
C. 500 ohms, /-53.1 degrees
D. 500 ohms, /53.1 degrees
Correct Answer: C

Explanation: The impedance of a series RC circuit is a complex quantity, combining resistance and reactance. Resistance (R) is the real component, while capacitive reactance (Xc) is the imaginary component, always negative for capacitors. 1. **Rectangular Impedance:** For a series circuit, impedance (Z) is R - jXc. Z = 300 ohms - j400 ohms. 2. **Magnitude:** The magnitude of impedance (|Z|) is calculated using the Pythagorean theorem: |Z| = sqrt(R^2 + Xc^2) |Z| = sqrt(300^2 + (-400)^2) |Z| = sqrt(90,000 + 160,000) = sqrt(250,000) = 500 ohms. 3. **Phase Angle:** The phase angle (theta) is found using the arctangent function: theta = arctan(Xc / R) theta = arctan(-400 / 300) = arctan(-1.333...) theta = -53.13 degrees (approximately). The negative sign indicates a capacitive circuit where current leads voltage. Therefore, the impedance in polar coordinates is 500 ohms, /-53.1 degrees. This matches option C. Options A and B have incorrect magnitudes. Option D has the correct magnitude but an incorrect positive angle, which would represent an inductive circuit.

Pass Your FCC Exam!

Study offline, track your progress, and simulate real exams with the GMDSS Trainer app.


Includes Elements 1, 3, 6, 7R, 8, and 9.