FCC Exam Question: 3-10B6
What is the maximum rated current-carrying capacity of a resistor marked “2000 ohms, 200 watts”?
Explanation: To determine the maximum current, we use the power formula P = I²R, where P is power in watts, I is current in amperes, and R is resistance in ohms. Given: Resistance (R) = 2000 ohms Power (P) = 200 watts Rearranging the formula to solve for current (I): I² = P / R I = √(P / R) Substitute the given values: I = √(200 watts / 2000 ohms) I = √(1 / 10) I = √0.1 I ≈ 0.316 amps Therefore, the maximum rated current-carrying capacity is approximately 0.316 amps. Options B, C, and D are incorrect as they result from miscalculations or incorrect formula application, leading to significantly higher current values that would exceed the resistor's power rating.
3-74L3
3-76L1
3-74L5
3-33E5
3-44F2
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Includes Elements 1, 3, 6, 7R, 8, and 9.