Subelement A: — Topic :
Question 6A102
Element 6 (Radiotelegraph)If L and C in a parallel resonant circuit resonants at 1000 kHz are so varied that their product remainsconstant, what will be the resulting resonant frequency?
Explanation
The resonant frequency ($f_r$) of a parallel LC circuit is determined by the formula: $f_r = \frac{1}{2\pi\sqrt{LC}}$.
In this scenario, the initial resonant frequency is 1000 kHz. The problem states that L and C are varied, but their *product* (LC) remains constant.
Since $2\pi$ is a mathematical constant and the product LC remains constant, the entire denominator ($2\pi\sqrt{LC}$) of the resonant frequency formula remains unchanged. Consequently, if the denominator is constant, the resonant frequency itself must also remain constant.
Therefore, the resulting resonant frequency will be the same as the original frequency. 1000 kHz is equivalent to 1 MHz. Thus, the resonant frequency remains 1 MHz.
Related Questions
6A100 To double the resonant frequency of a resonant circuit:6A101 How may the Q of a parallel resonant circuit be increased?6A103 What is the resonant frequency of a tuned circuit consisting of a 500 picofarad capacitor, a 150microfarad tuning coil, and 10 ohms resistance?6A104 What is voltage regulation as applied to power supplies?6A105 An EMF may be generated by sound waves by what principle?