FCC Exam Question: 8-43E2

Resistive losses in a waveguide are very small because:

A. The inner surface of the waveguide is large.
B. The inner surface of the waveguide is small.
C. The waveguide does not require a ground connection.
D. The heat remains in the waveguide and cannot dissipate.
Correct Answer: A

Explanation: Waveguides operate at microwave frequencies where the "skin effect" is pronounced. This phenomenon causes RF currents to flow predominantly on the inner surface of the conductor, rather than uniformly throughout its cross-section. Therefore, the larger the inner surface area (A), the more spread out these currents become. Distributing the current over a greater surface reduces the current density, which in turn significantly minimizes resistive heating losses (I²R losses). Conversely, a small inner surface (B) would concentrate the current, leading to higher current density and greater losses. The need for a ground connection (C) is unrelated to resistive losses. Option (D) describes heat *retention* if losses were present, rather than explaining *why* losses are small in the first place.

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Includes Elements 1, 3, 6, 7R, 8, and 9.