Explanation: The circuit shows two D-type flip-flops (FFs), U5-1 and U5-2, which are positive edge-triggered. 1. **D-type Flip-Flop Operation:** A D-type flip-flop latches the logic level present at its D (data) input and transfers it to its Q output on the active (rising) edge of the clock signal. 2. **Reset Inputs (Pins 1 and 4):** These are the active-low clear (CLR) or reset inputs. The problem states they are "high." This means the reset function is inactive, allowing the flip-flops to operate normally and respond to their clock and data inputs. (If they were low, the Q outputs would be forced low, regardless of D or clock.) 3. **Input Data (Pins 2 and 12):** Both D inputs (Pin 2 for FF1 and Pin 12 for FF2) are connected to Vcc, which represents a logic HIGH state. 4. **Clocking Sequence:** * **Clk A cycle:** The first clock cycle is applied to Clk A (Pin 3), which is the clock input for FF1. On the rising edge of Clk A, FF1 latches its D input (which is HIGH). Therefore, Pin 5 (Q output of FF1) goes HIGH. * **Clk B cycle:** The second clock cycle is applied to Clk B (Pin 11), the clock input for FF2. On the rising edge of Clk B, FF2 latches its D input (which is also HIGH). Therefore, Pin 9 (Q output of FF2) goes HIGH. After both clock cycles, both flip-flops have latched a HIGH input to their respective Q outputs. Thus, Pin 5 will be high and Pin 9 will be high. The final answer is $\boxed{D}$