Explanation: When capacitors are connected in parallel, their individual capacitances add together to form the total capacitance. This configuration effectively increases the total plate area available to store charge, similar to combining individual capacitor plates into a larger single one. To calculate the total capacitance ($C_T$), you simply sum the values of each capacitor: $C_T = C_1 + C_2 + C_3$ $C_T = 3 \mu F + 5 \mu F + 7 \mu F$ $C_T = 15 \mu F$ Therefore, the total capacitance is 15 microfarad. This matches option B. Options A (9 microfarad), C (10 microfarad), and D (3 microfarad) are incorrect because they do not represent the cumulative capacitance of all three components when connected in parallel.