Explanation: To determine the maximum current a resistor can safely carry, we use the relationship between power, current, and resistance, derived from Ohm's Law. The relevant formula is P = I²R, where P is power in watts, I is current in amperes, and R is resistance in ohms. We need to solve for current (I), so we rearrange the formula: I² = P / R I = √(P / R) Now, plug in the given values: P = 200 watts R = 5000 ohms I = √(200 W / 5000 Ω) I = √(2 / 50) I = √(1 / 25) I = 1 / 5 I = 0.2 A Therefore, the maximum current carrying capacity is 0.2 amperes. Options B and C are incorrect as they result from misapplying the formula or calculation errors.