FCC Exam Question: 6A25

What factors determine the charge stored in a capacitor?

A. Capacitance of the capacitor
B. The applied voltage
C. Both A & B
D. None of the above
Correct Answer: C

Explanation: The charge (Q) stored in a capacitor is directly proportional to its capacitance (C) and the voltage (V) applied across it. This relationship is described by the fundamental formula: **Q = C * V**. * **Capacitance (C)** is the inherent ability of the capacitor to store an electric charge for a given voltage. A larger capacitance means the capacitor can store more charge at the same voltage. * **The applied voltage (V)** determines the "pressure" or potential difference driving the charge onto the capacitor plates. A higher voltage will force more charge onto a capacitor of a given capacitance. Therefore, both the physical property of the capacitor (its capacitance) and the external electrical condition (the applied voltage) are necessary to determine the total charge stored. Answers A and B are incorrect because neither factor alone is sufficient to define the stored charge; both interact as per the formula.

Pass Your FCC Exam!

Study offline, track your progress, and simulate real exams with the GMDSS Trainer app.


Includes Elements 1, 3, 6, 7R, 8, and 9.