FCC Exam Question: 6A25
What factors determine the charge stored in a capacitor?
Explanation: The charge (Q) stored in a capacitor is directly proportional to its capacitance (C) and the voltage (V) applied across it. This relationship is described by the fundamental formula: **Q = C * V**. * **Capacitance (C)** is the inherent ability of the capacitor to store an electric charge for a given voltage. A larger capacitance means the capacitor can store more charge at the same voltage. * **The applied voltage (V)** determines the "pressure" or potential difference driving the charge onto the capacitor plates. A higher voltage will force more charge onto a capacitor of a given capacitance. Therefore, both the physical property of the capacitor (its capacitance) and the external electrical condition (the applied voltage) are necessary to determine the total charge stored. Answers A and B are incorrect because neither factor alone is sufficient to define the stored charge; both interact as per the formula.
6A153
6A118
6A574
6A365
6A189
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Includes Elements 1, 3, 6, 7R, 8, and 9.