FCC Exam Question: 6A232
What is the DC plate voltage of a resistance-coupled amplifier state with a plate-supply voltage of 260 V,a plate current of 1 mA, and a plate load resistance of 100,000 ohms?
Explanation: In a resistance-coupled amplifier, the DC plate voltage (Vp) is the plate supply voltage minus the voltage drop across the plate load resistor. This voltage drop occurs due to the plate current flowing through the resistor. First, calculate the voltage drop across the plate load resistor using Ohm's Law (V = I * R): Voltage drop = Plate Current * Plate Load Resistance Voltage drop = 1 mA * 100,000 ohms = 0.001 A * 100,000 ohms = 100 V Next, subtract this voltage drop from the plate supply voltage to find the DC plate voltage: DC Plate Voltage = Plate Supply Voltage - Voltage drop DC Plate Voltage = 260 V - 100 V = 160 V Therefore, the DC plate voltage is 160 V. Options B, C, and D are incorrect as they do not result from this calculation. Option B (100 V) is the voltage drop, not the actual plate voltage.
6A84
6A506
6A213
6A52
6A305
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Includes Elements 1, 3, 6, 7R, 8, and 9.