FCC Exam Question: 6A225

When a tube is used as a Class B amplifier what portion of the excitation voltage cycle does plate currentflow?

A. Slightly more than 180 degrees
B. Slightly less than 180 degrees
C. 360 degrees
D. None of the above
Correct Answer: A

Explanation: In a Class B amplifier, the active device (tube in this case) is biased at or very near cutoff. This means that plate current flows for approximately one-half, or 180 degrees, of the input excitation voltage cycle. Option A, "Slightly more than 180 degrees," is correct because practical Class B amplifiers, especially in push-pull configurations, are often biased *just above* cutoff. This slight offset prevents "crossover distortion" – a noticeable distortion that occurs when the current from one half of the amplifier circuit turns off before the other half fully turns on. By allowing a small overlap, conduction occurs for a few degrees more than 180, ensuring a smoother transition and cleaner output signal. Option B, "Slightly less than 180 degrees," would typically result in severe crossover distortion and is characteristic of Class C operation if significantly less. Option C, "360 degrees," describes Class A amplifier operation, where the tube conducts for the entire input cycle.

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Includes Elements 1, 3, 6, 7R, 8, and 9.