Question 3-61I5

To determine the total current flow, first calculate the equivalent resistance of the two parallel light bulbs. For two equal resistors in parallel, the equivalent resistance is half of one resistor: $R_{parallel} = \frac{12 \text{ ohms}}{2} = 6 \text{ ohms}$. Next, sum this parallel resistance with the battery's internal resistance, which is in series with the bulbs, to find the total circuit resistance: $R_{total} = R_{parallel} + R_{internal} = 6 \text{ ohms} + 1.2 \text{ ohms} = 7.2 \text{ ohms}$. Finally, apply Ohm's Law ($I = \frac{V}{R}$) to find the total current: $I = \frac{6 \text{ volts}}{7.2 \text{ ohms}} \approx 0.833 \text{ amps}$. This calculation matches option B. The other options result from incorrect resistance calculations or Ohm's Law application.