Subelement D: Circuits— Topic 29: R-L-C Circuits
Question 3-29D3
Element 3 (GROL)How could voltage be greater across reactances in series than the applied voltage?
Explanation
At **resonance** in a series RLC circuit, the inductive reactance ($X_L$) and capacitive reactance ($X_C$) are equal in magnitude and 180 degrees out of phase. This causes them to effectively cancel each other out, leading to a very low total impedance (ideally just the resistance).
A low impedance allows a large current to flow through the circuit. Even though the reactive voltages $V_L = I \times X_L$ and $V_C = I \times X_C$ are also 180 degrees out of phase and sum to zero across the reactive part, their *individual magnitudes* can become much larger than the applied source voltage due to the large current flowing through potentially high reactances. This phenomenon is called voltage magnification or Q-magnification, where significant energy oscillates between the inductor and capacitor.
Resistance (A) and conductance (B) are measures of opposition to current flow but do not explain voltage magnification. Capacitance (C) is a component, but the magnification effect only occurs when it interacts with inductance at a specific frequency, i.e., at resonance.
Related Questions
3-29D1 What is the approximate magnitude of the impedance of a parallel R-L-C circuit at resonance?3-29D2 What is the approximate magnitude of the impedance of a series R-L-C circuit at resonance?3-29D4 What is the characteristic of the current flow in a series R-L-C circuit at resonance?3-29D5 What is the characteristic of the current flow within the parallel elements in a parallel R-L-C circuit at resonance?3-29D6 What is the relationship between current through a resonant circuit and the voltage across the circuit?