Subelement B: Electrical Math— Topic 18: Calculations
Question 3-18B1
Element 3 (GROL)What is the magnitude of the impedance of a series AC circuit having a resistance of 6 ohms, an inductive reactance of 17 ohms, and zero capacitive reactance?
Explanation
In a series AC circuit, resistance (R) and reactance (X) are out of phase and do not add arithmetically. Resistance represents energy dissipation, while reactance represents energy stored and released. Inductive reactance (XL) causes current to lag voltage, while capacitive reactance (XC) causes current to lead voltage.
The magnitude of the total impedance (Z) in a series RLC circuit is calculated using the Pythagorean theorem:
$Z = \sqrt{R^2 + (X_L - X_C)^2}$
Given:
Resistance (R) = 6 ohms
Inductive Reactance (XL) = 17 ohms
Capacitive Reactance (XC) = 0 ohms
Plugging in the values:
$Z = \sqrt{6^2 + (17 - 0)^2}$
$Z = \sqrt{6^2 + 17^2}$
$Z = \sqrt{36 + 289}$
$Z = \sqrt{325}$
$Z \approx 18.03 \text{ ohms}$
Therefore, the magnitude of the impedance is approximately 18 ohms.
Option C is correct because it results from the vector sum of resistance and reactance. Options A, B, and D are incorrect as they do not apply the correct formula for combining resistance and reactance in a series AC circuit. For instance, D (23 ohms) would be the arithmetic sum (6 + 17), which is incorrect because resistance and reactance are 90 degrees out of phase.
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